WitrynaAdd a comment. 1. For 3 balls of red color. P r o b = 3 12 ⋅ 2 11 ⋅ 1 10. For 3 balls of green color. P r o b = 4 12 ⋅ 3 11 ⋅ 2 10. For 3 balls of blue color. P r o b = 5 12 ⋅ 4 11 ⋅ 3 10. Total probability of all ball same color is. Witryna23.Suppose you choose a marble from a bag containing 6 red marbles, 3 white marbles, and 4 blue marbles. You return the first marble to the bag and then choose again. Find P(red and blue). a. 10/13 b. 9/13 c. 24/169 d. 24/13. 1 answer; math; asked by Anonymous; 532 views

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WitrynaMath Statistics I have a bag containing 40 blue marbles and 60 red marbles. I choose 10 marbles (without replacement) at random. Let X be the number of blue marbles and y be the number of red marbles. Find the joint PMF of X and Y. I have a bag containing 40 blue marbles and 60 red marbles. I choose 10 marbles (without replacement) at … WitrynaImagine that you have a bag containing 10 marbles of different colors. You have drawn a marble, recorded its color, and replaced it fifty times, with the following … grassroots ecology

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Witryna11 kwi 2024 · What is the probability that you get two yellow marbles? I would say the answer is 1 6. There is a single combination to draw two yellow marbles and 6 possible combinations how to draw two marbles. My second approach is: possibility of picking the first one yellow is 1 2, picking the second one yellow is 1 3, multiplying possibilities … WitrynaImagine that you have a bag containing 10 marbles of different colors. You have drawn a marble, recorded its color, and replaced it fifty times, with the following results: 9 purple, 16 orange, 6 yellow, and 19 green marbles. Make a prediction for how many marbles of each color are in the bag. Show all of your work or explain your reasoning. 2. Witryna21 lut 2024 · The hypergeometric PMF of the number X of red marbles in two draws without without replacement from a bag of 10 marbles of which 3 are red is as follows: P ( X = k) = ( 3 k) ( 7 2 − k) ( 10 2). for k = 0, 1, 2. From R statistical software we have the following PMF table and bar chart: These are the same as the values P ( X = 0) = P ( … chlamydospore in fungi